3x+16=x^2

Solution for 3x+16=x^2 equation:

3x+16=x^2

We move all terms to the left:

3x+16-(x^2)=0

determiningTheFunctionDomain
-x^2+3x+16=0

We add all the numbers together, and all the variables

-1x^2+3x+16=0

a = -1; b = 3; c = +16;
Δ = b2-4ac
Δ = 32-4·(-1)·16
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{73}}{2*-1}=\frac{-3-\sqrt{73}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{73}}{2*-1}=\frac{-3+\sqrt{73}}{-2}
$